Wednesday, March 4, 2009

DAN's TACIT - I've learned something from Dan today...if NH3 is 0.5ppm, to eliminate it is with 0.5 x 0.9 = 4.5ppm Cl2 . Max that we have here with two pumps = 700kg x1,000/55,000m3 = 12.7 ppm Cl2 where 12.7-4.5=8.2ppm extra Cl2. To get 2.0ppm we must dose 4.0ppm therefore 8.2-4.0=4.2ppm. In conclusion, we could treat...THANKS to DAN...watch out behind the white board...